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10=0.018268v^2
We move all terms to the left:
10-(0.018268v^2)=0
We get rid of parentheses
-0.018268v^2+10=0
a = -0.018268; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-0.018268)·10
Δ = 0.73072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.73072}}{2*-0.018268}=\frac{0-\sqrt{0.73072}}{-0.036536} =-\frac{\sqrt{}}{-0.036536} $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.73072}}{2*-0.018268}=\frac{0+\sqrt{0.73072}}{-0.036536} =\frac{\sqrt{}}{-0.036536} $
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